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x^2/3-3=33
We move all terms to the left:
x^2/3-3-(33)=0
We add all the numbers together, and all the variables
x^2/3-36=0
We multiply all the terms by the denominator
x^2-36*3=0
We add all the numbers together, and all the variables
x^2-108=0
a = 1; b = 0; c = -108;
Δ = b2-4ac
Δ = 02-4·1·(-108)
Δ = 432
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{432}=\sqrt{144*3}=\sqrt{144}*\sqrt{3}=12\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{3}}{2*1}=\frac{0-12\sqrt{3}}{2} =-\frac{12\sqrt{3}}{2} =-6\sqrt{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{3}}{2*1}=\frac{0+12\sqrt{3}}{2} =\frac{12\sqrt{3}}{2} =6\sqrt{3} $
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